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Informatika - 2021./22. jesen - 12.

12. Koji će od navedenih algoritama u najmanje koraka ispisati djelitelje prirodnoga broja n većega od 1?

A.	Python	C
	$\begin{aligned} & \text{for i in range(1, n + 1):} \ & \qquad \begin{aligned} & \text{if n \% i == 0:} \ & \qquad \qquad \text{print(n)} \end{aligned} \end{aligned}$	$\begin{aligned} & \text{int n;} \ & \text{for (int i=1; i<n+1; i++)} \ & \qquad \text{if (n \% i == 0)} \ & \qquad \qquad \text{printf("\%d", n);} \end{aligned}$

B.	Python	C
	$\begin{aligned} & \text{for i in range(2, n + 1):} \ & \qquad \begin{aligned} & \text{if n \% i == 0:} \ & \qquad \qquad \text{print(i)} \end{aligned} \end{aligned}$	$\begin{aligned} & \text{int n;} \ & \text{for (int i=2; i<n+1; i++)} \ & \qquad \text{if (n \% i == 0)} \ & \qquad \qquad \text{printf("\%d", i);} \end{aligned}$

C.	Python	C
	$\begin{aligned} & \text{for i in range(2, round(n**0.5) + 1):} \ & \qquad \begin{aligned} & \text{if n \% i == 0:} \ & \qquad \qquad \text{print(i)} \end{aligned} \ & \text{print(n)} \end{aligned}$	$\begin{aligned} & \text{int n;} \ & \text{for (int i=2; i<round(sqrt(n))+1; i++)} \ & \qquad \text{if (n \% i == 0)} \ & \qquad \qquad \text{printf("\%d", i);} \ & \text{printf("\%d", n);} \end{aligned}$

D.	Python	C
	$\begin{aligned} & \text{for i in range(1, n // 2 + 1):} \ & \qquad \begin{aligned} & \text{if n \% i == 0:} \ & \qquad \qquad \text{print(i)} \end{aligned} \ & \text{print(n)} \end{aligned}$	$\begin{aligned} & \text{int n;} \ & \text{for (int i=1; i<n/2+1; i++)} \ & \qquad \text{if (n \% i == 0)} \ & \qquad \qquad \text{printf("\%d", i);} \ & \text{printf("\%d", n);} \end{aligned}$

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