Informatika - 2018./19. ljeto - 15.

A. $y=\mathrm{sqr}(a+b\ast x+y)\mathrm{/}abs(a+b+x+y)y=\backslash operatorname\{sqr\}(a+b\; *\; x+y)\; /\; a\; b\; s(a+b+x+y)$

B. $y=\mathrm{sqr}(a+b+x+y)\mathrm{/}abs(a+b)+abs(x+y)y=\backslash operatorname\{sqr\}(a+b+x+y)\; /\; a\; b\; s(a+b)+a\; b\; s(x+y)$

C. $y=\mathrm{sqr}(a+b+x+y)\mathrm{/}(abs(a+b)+abs(x+y))y=\backslash operatorname\{sqr\}(a+b+x+y)\; /(a\; b\; s(a+b)+a\; b\; s(x+y))$

D. $y=\mathrm{sqr}(a+b\ast x+y)\mathrm{/}(abs(a+b)+abs(x+y))y=\backslash operatorname\{sqr\}(a+b\; *\; x+y)\; /(a\; b\; s(a+b)+a\; b\; s(x+y))$