Matematika B - 2010. ljeto, 5.

A. $\frac{3a^2+6a+1}{9}\backslash frac\{3\; a^\{2\}+6\; a+1\}\{9\}$

B. $\frac{9a^2+6a+1}{9}\backslash frac\{9\; a^\{2\}+6\; a+1\}\{9\}$

C. $\frac{9a^2+3a+1}{3}\backslash frac\{9\; a^\{2\}+3\; a+1\}\{3\}$

D. $\frac{3a^2+3a+1}{3}\backslash frac\{3\; a^\{2\}+3\; a+1\}\{3\}$